A USB3 area scan camera usually runs on the port's power alone. Models that draw more add an auxiliary power pin on the GPIO connector so the cabinet can feed a higher DC rail directly — and that is where the questions start: which source wins when both are connected, how big the supply must be, and whether the USB cable can finally come out. This guide answers all three. You will size the feed with a worked example, weigh a lower feed voltage against a higher one, and leave with a pre-power-up checklist. The camera side is any USB3 model from the area scan cameras range whose I/O sheet shows an auxiliary power pin.
What happens when the auxiliary feed and USB power are connected at the same time?
The camera's input stage ORs the two supplies, and the higher voltage wins: a 12 V auxiliary feed carries essentially the whole camera load, while the USB rail stays connected for data and start-up. Neither connection replaces the other.
The ORing uses one element per input. A diode-OR design puts a series diode on each feed; an ideal-diode design drives a MOSFET to behave like a near-perfect diode. Whichever source sits higher after its element conducts and carries the load, and the lower source is back-biased into contributing nothing. The comparison happens about 0.3 to 0.4 V below each rail with a Schottky diode, about 0.7 V with silicon, or within tens of millivolts with an ideal-diode controller. Those offsets are small against the 7 V gap between the auxiliary rail and the 5 V USB rail, so the auxiliary feed wins decisively.
What moves the split is the gap, not the camera. A 5 V auxiliary feed would tie with VBUS and share the load by cable and source impedance, which is exactly why auxiliary inputs are specified well above the USB rail.
Why does the camera still need the USB 5 V rail to start up?
The camera does not enumerate without VBUS: the start-up logic and the USB link electronics take their power from the 5 V rail, so a board fed only through the auxiliary pin has power on it but never appears as a device. The auxiliary feed is the muscle; the USB cable is the address.
That is why the pin is called auxiliary: it supplements the USB connection and never replaces it. Keep the USB cable in for data, enumeration and the initial power-up sequence, and size the auxiliary feed for the camera's real load. If the status LED is lit yet the host lists no device, the fault is on the USB leg, and the camera has power but not detected checks apply unchanged.
Keep the USB leg short and solid. A high-flex cable such as the LS-CBL-0219, 3 m and drag-chain rated, sits at the practical ceiling for a passive USB 3.0 run; past it, expect speed fallback before you expect clean full-rate streaming.
Which pin carries power and which pins are signal only?
Only the pin the camera's I/O sheet marks as auxiliary power in may carry supply current; the rest of the GPIO block is opto-isolated signal lines sized for a few tens of milliamps, and supply voltage pushed into one of them burns the input stage on contact.
An opto-isolated trigger input is an LED behind a series resistor, sized so a logic-level signal lights it gently. It is an input in the electronics sense, not a power entry: its current path is milliamperes, with no trace width or protection behind it for half an amp. Before the harness is drawn, work out which side of an opto-isolated GPIO circuit is the input, then run the GPIO wiring checks that prevent damage on the drawing, not on the assembled cabinet.
If the pinout shows no auxiliary power pin, the camera has no second source: all of its power arrives through the main power connector, and the GPIO block stays signals only.
How much current does the auxiliary feed need?
Divide the camera's power figure by the feed voltage and add margin: a 6 W camera on a 12 V feed draws 6 / 12 = 0.5 A, so a regulated 1 A supply at that voltage covers the load with room for inrush and cable loss.
Worked example, with 6 W — a figure you can read off the power line of most mid-size USB3 camera sheets — and a 5 m run on a 26 AWG pair at 0.134 Ω/m:
- Input current: 6 W / 12 V = 0.5 A.
- Loop resistance: 0.134 Ω/m × 10 m of conductor (5 m out, 5 m back) = 1.34 Ω.
- Cable drop: 0.5 A × 1.34 Ω = 0.67 V, so 11.3 V reaches the connector.
- Worst case supply: 12 V − 5 % = 11.4 V, minus the 0.67 V drop, leaves 10.7 V at the camera.
Fix it by conductor or by voltage: a 24 AWG pair (0.084 Ω/m, 0.84 Ω loop) cuts the drop to 0.42 V, and doubling the feed voltage to 24 V halves the current to 0.25 A and the drop to 0.34 V. The decision for this case: a regulated supply rated 1 A at the feed voltage, on a 24 AWG pair, fused at the supply.
Land the harness on a power-and-I/O cable with an open end, so the power pair, the trigger pair and the ground arrive as labelled leads. The LS-CBL-0300 is an M8 8-pin male-to-open 8-core cable, 7 m, drag-chain rated for a moving axis.
- Type
- Power and I/O cables
- Length
- 6-8 m
Both legs of the harness — the power leg above and the USB leg earlier — come from the camera cables page, filtered by connector and length.
Is a higher feed voltage better than a lower one?
For the same camera, doubling the feed voltage halves the feed current and the cable drop, but the camera's switching regulator dissipates slightly more at the higher input voltage: the higher rail wins on long runs and in cabinets already wired for it, the lower wins on short runs.
The two effects pull in opposite directions. On the cable, current halves, so the 0.67 V drop of the worked example falls to 0.34 V over the same 1.34 Ω loop. Inside the camera, a hard-switched buck regulator loses a little more in every switching cycle as input voltage rises, so efficiency edges down: with typical small-regulator figures of 90 % at the lower rail and 88 % at the higher one, a camera needing 5 W internally draws 5 / 0.90 = 5.6 W on a 12 V feed against 5 / 0.88 = 5.7 W on 24 V. The difference is about 0.1 W, and it is dissipated inside the camera body, next to the sensor.
So the choice is per case. Feed 24 V when the run exceeds about 10 m, or when the panel already distributes 24 V and you want the thinner cable and the smaller drop. Feed 12 V when the run is short and a 12 V rail already exists; adding a converter just to make the higher voltage throws the advantage away.
When is auxiliary power worth the extra wire?
Add the feed when the camera's draw exceeds what the port guarantees — 2.5 W on USB 2.0, 4.5 W on USB 3.0 — or the run is long enough that 5 V sags; skip it when the camera sits well inside the budget.
A USB port funds the camera, not just the data. USB 2.0 guarantees 500 mA at 5 V, which is 2.5 W; USB 3.0 guarantees 900 mA, which is 4.5 W. A camera that needs more than its port's figure has no guarantee behind it, and the failure looks the same every time: the camera enumerates at idle, then disconnects or drops frames at full frame rate and full resolution. A camera detected but showing no image is the milder form of the same fault, as the USB power budget checks for a detected-but-dark camera walk through, and the budgets stack fast once you count how many USB cameras one controller can feed before the host gives up.
Three cases decide it:
- Stated camera power above the port's guarantee: the auxiliary feed is not optional; it is the only supply sized for the load.
- Power at or near the guarantee on a 3 m or longer USB run: add the feed, because cable resistance steals from a rail with no headroom.
- Power well under the guarantee on a short run: skip the extra pair. Fewer conductors, fewer faults, one less supply to fail.
GigE cameras meet the same question through PoE rather than a GPIO pin, and where a PoE camera gets link but no power the injector and its power class are the equivalent first check.
What do you check before the first power-up?
Check five things with the feed still switched off: the auxiliary pin is the one the I/O sheet marks, both grounds are common, the feed is fused at the supply, polarity is confirmed on the open leads, and no power-rated conductor lands on a signal pin.
- Pin identity: match every lead to the camera's I/O sheet. Supply current goes to the auxiliary power pin only.
- Common ground: tie the supply's 0 V to the camera's ground. The ORing stage and every trigger input need one reference, and a floating supply shifts both.
- Fuse: a 1 A fuse at the supply end protects the cable of a 0.5 A feed. Size the fuse for the wire, not for the camera.
- Polarity: M8 and 12-pin connectors are keyed, open leads are not, so ring the leads out to the pins before the supply is connected.
- Under load: stream at full frame rate and measure the feed at the connector. A feed that dips when the sensor reads out will return later as disconnects, not as an image defect.
Decision in one line: keep the USB cable in for data and start-up, run a fused auxiliary feed into the auxiliary power pin through a common-ground power-and-I/O cable, and size the supply at roughly twice the camera's wattage. Pick the camera side in the camera configurator, the harness side in the accessories finder, and the remaining wiring checks on the systems topic page.
Questions
Does the camera draw from USB and the auxiliary supply at the same time?
No. The ORing stage hands the load to whichever source sits at the higher voltage, so the auxiliary feed carries essentially the entire camera and the 5 V rail idles. The USB link still carries the image data and keeps the start-up rail alive, which is why both cables stay connected for the life of the installation.
What happens if the auxiliary supply drops out while the camera is streaming?
The 5 V rail takes the load the instant the auxiliary feed falls below it. A camera chosen for auxiliary power usually draws more than the 4.5 W a USB 3.0 port guarantees, so the rail then collapses: frames drop or the device disconnects. A supply that sags under load is worse than one that fails clean, because the failure arrives mid-inspection.
Can the trigger signal share a conductor with the auxiliary power?
Run them on separate conductors. The trigger input wants voltage and a few milliamps through its optocoupler; the power pair carries half an amp or more. Sharing one conductor couples every load-current dip into each trigger edge, which shows up as frame-to-frame timing jitter. The only thing the two circuits should share is the ground reference.
Do GigE cameras use the same two-source arrangement?
No. A GigE camera has no USB rail to satisfy: all of its power arrives through its power connector, or through the Ethernet cable itself when PoE is supported. The budget then comes from the PoE power class, 12.95 W at the camera for a Class 0 device under IEEE 802.3af, so the arithmetic changes shape but not method.

